JSI Tip 8150. How do I remove the last N characters of a string?

I have scripted StripString.bat to remove the last N characters of a string.

The syntax for using StripString.bat is:

call StripString String newString \[Numchar\]

Where:

String      is the variable name that contains the string.
newString   is a call directed environment variable that will contain the new string, and
Numchar     is an optional parameter that contains N, the number of characters to remove. The default is 1.

Example

@echo off
set string=123456789
call stripstring string newstring
@echo string=%string%, newstring=%newstring%
call stripstring string newstring 8
@echo string=%string%, newstring=%newstring%

displays

string=123456789, newstring=12345678
string=123456789, newstring=1

StripString.bat contains:

@echo off
if \{%2\}\{\}  @echo Syntax: StripString String newVar \[NumChar\]&goto :EOF
if not \{%3\}\{\} (
 call set %2=%%%1:~0,^-%3%% 
 ) else (
 call set %2=%%%1:~0,^-1%%
)

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JSI Tip 8150. How do I remove the last N characters of a string?

\{\} @echo Syntax: StripString String newVar \[NumChar\]&goto :EOF if not \{%3\}

Comments

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